The square roots of -81 are ±9i where i is the imaginary square root of -1.
The square root of 1/100 is 1/10
1/2
81 -- 8+1 = 9 -- square root of 81 = 9
It is i/3 where i is the imaginary number which is the square root of -1.
-1/9
The square roots of -81 are ±9i where i is the imaginary square root of -1.
(y2/81)1/2 = y/9
x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
the square root of (1/4) is 1/2
The square root of 1/100 is 1/10
1/2
81 -- 8+1 = 9 -- square root of 81 = 9
Try the square roots of 1 and 6561, which are 1 and 81. Their difference is 80 which is one less than 81. And that is the square of 9. In fact this works whenevr the first of the two numbers is a square number. So the purpose of the question is not clear.
The square root of 1 over 15 is a constant and so differentiating it gives 0.
It is i/3 where i is the imaginary number which is the square root of -1.
1 over 6