(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
5
2x2+9 = -412x2 = -41-92x2 = -50x2 = -25x = -5Check: (2*-52)+9 = -41Sorry, you can't have -5 as square root of -25.x = 5i, where i is the imaginary square root of -1
Is this 3*sqrt((x+25)*x)=0 or 3*sqrt(x+25x)=0 or 3*sqrt(x)+25x=0 or 3*sqrt(x+25)*x=0? I'm not going to bother answering all possible interpretations, but here's a hint: square the equation to get rid of the square root operation first. Then solving it will be easy.
5x
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
5
25x (square) plus 40 plus 15 equals 680.
2x2+9 = -412x2 = -41-92x2 = -50x2 = -25x = -5Check: (2*-52)+9 = -41Sorry, you can't have -5 as square root of -25.x = 5i, where i is the imaginary square root of -1
Is this 3*sqrt((x+25)*x)=0 or 3*sqrt(x+25x)=0 or 3*sqrt(x)+25x=0 or 3*sqrt(x+25)*x=0? I'm not going to bother answering all possible interpretations, but here's a hint: square the equation to get rid of the square root operation first. Then solving it will be easy.
If you mean: x2-25x+100 then it is (x-5)(x-20) when factored
625ft² = 58.06m²
f'(x)=.5x^-.5 f''(x)=-.25x^-1.5 f'''(x)=.375x^-2.5 or f'''(x)=(3/8)x^(-5/2)
The GCF is 5x.
Substitution method: from first equation y = 5x - 8. In the second equation this gives 25x - 5(5x - 8) = 32 ie 25x - 25x + 40 = 32 ie 40 = 32 which is not possible, so the system has no solution. Multiplication method: first equation times 5 gives 25x - 5y = 40, but second equation gives 32 as the value of the identical expression. No solution.