The square root of 4 is 2, if you multiply that by the square root of 49, which is 7, you get 14.
49
49
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
2 root 3 over 2, so square root of 3
98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
The square root of 4 is 2, if you multiply that by the square root of 49, which is 7, you get 14.
if you're squaring a square root, your're getting the number back. lets say it was square root (49)2 the square root of 49 is 7, 7 2 is 49 if you do it the other way 492=2352, this square root is 49, so the answer is 48AB
sqrt(4/49) = sqrt(4)/sqrt(49) = 2/7
49
49
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
It is 49*sqrt(2).
2 root 3 over 2, so square root of 3
Square root of 40 can be written as 49 to the power of half. So, the 2 in the half gets cancelled with the 4 leaving 49 square. And 49 square is 2401.
you find what same 2 numbers equal that number EXAMPLE: what is the square root of 49? ANSWER:7 because 7x7=49 Edit: Nearly there. 7 is the PRINCIPAL square root but there is another, which is -7. (-7)*(-7) is also 49.
To find the square root of 9604, we first need to identify the factors of the number. 9604 can be expressed as 2^2 * 2401, where 2401 is a perfect square. Taking the square root of 2401 gives us 49. Therefore, the square root of 9604 is 2 * 49, which equals 98.