root of p = 67 square both sides p = 67 times 67 =4,489
A=s2 64=s2 s=8 units P=4s P=4(8) P=32 units Therefore, the perimetre is 32 units.
To cube something is to raise to the third power. P cubed would be p^3
Yes, the square root of 31 is an irrational number. Rational numbers are those which can be expressed in the form of p/q(where p, q are integers and q ≠0). Square root of 31 has non-terminating and non-repeating decimal so it can't be expressed in the form of p/q.
Only if p and q are DIFFERENT primes.
p=9
Yes, the square root is equivalent to an exponent of 1/2.Suppose the exponent is a rational number of the form p/q where p and q are integers and q > 0. Then x^(p/q) = (the qth root of x) raised to the power p or, equivalently, (the qth root of (x raised to the power p).
root of p = 67 square both sides p = 67 times 67 =4,489
18p = the square root of 3600 18p = 60 p = 60/18 p = 3 and a 1/3
One cannot get the square root of an item. However if you want to quantify this item: The square root of the moon = the square root of (1) the moon. The square root of (1) moon is still one moon as the root of 1 is still one :P
By an indirect proof. Assuming the square root is rational, it can be written as a fraction a/b, with integer numerator and denominator (this is basically the definition of "rational"). If you square this, you get a2/b2, which is rational. Hence, the assumption that the square root is rational is false.
A=s2 64=s2 s=8 units P=4s P=4(8) P=32 units Therefore, the perimetre is 32 units.
To cube something is to raise to the third power. P cubed would be p^3
Square root of 53 is simlipfied in decimal form as √53 = 7.280. Square root of 53 cannot be expressed as a fraction in the form p/q which tells us that the square root of 53 is an irrational number.
Yes, the square root of 31 is an irrational number. Rational numbers are those which can be expressed in the form of p/q(where p, q are integers and q ≠0). Square root of 31 has non-terminating and non-repeating decimal so it can't be expressed in the form of p/q.
P cubed
Only if p and q are DIFFERENT primes.