2 root 3 over 2, so square root of 3
About 0.39223227
One third
the square root of 1936 is 2 x 2 x 2 x 2 x 11 x11 Therefore : 2 x 2 x11 = 44 (answer)
2 radical 11 the square root of 44. 44/2 = 22 radical 2 x 22 radical 2 x 2 x 11 Since 2 is under the radical twice you can take it out 2 radical 11
3x^2 = 44 divide both sides by 3; x^2 == 44/3 x = +,- square root of 44/3 write 44 = 4 x 11; x = +,- 2(square root of 11/3) multiply the square root of 11/3 by square root of 3/3; x = +,- (2/3)(square root of 33)
2 times the square root of 11
2 root 3 over 2, so square root of 3
22
About 0.39223227
One third
the square root of 1936 is 2 x 2 x 2 x 2 x 11 x11 Therefore : 2 x 2 x11 = 44 (answer)
The square root of 2 is irrational, and therefore, this equation is unsolvable.
2 radical 11 the square root of 44. 44/2 = 22 radical 2 x 22 radical 2 x 2 x 11 Since 2 is under the radical twice you can take it out 2 radical 11
wow u cant figure out awnser relly the At first you will multiply the, (1 divided by 2 square root of 2) by (2square root of 2 divided by 2 square root of 2) because 2 square root of 2 is irrational. so the answer is square root of 2 over 4.
The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5
cos pi over four equals the square root of 2 over 2 This value can be found by looking at a unit circle. Cos indicates it is the x value of the point pi/4 which is (square root 2 over 2, square root 2 over 2)