The square root of 4 is 2, if you multiply that by the square root of 49, which is 7, you get 14.
49
49
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
7^2 or 49.
98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
The square root of 4 is 2, if you multiply that by the square root of 49, which is 7, you get 14.
if you're squaring a square root, your're getting the number back. lets say it was square root (49)2 the square root of 49 is 7, 7 2 is 49 if you do it the other way 492=2352, this square root is 49, so the answer is 48AB
49
49
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
10 ft Because 102+102 = 200 and the square root of this is 10 times the square root of 2 which complies with Pythagoras' theorem.
It is 49*sqrt(2).
Square root of 40 can be written as 49 to the power of half. So, the 2 in the half gets cancelled with the 4 leaving 49 square. And 49 square is 2401.
you find what same 2 numbers equal that number EXAMPLE: what is the square root of 49? ANSWER:7 because 7x7=49 Edit: Nearly there. 7 is the PRINCIPAL square root but there is another, which is -7. (-7)*(-7) is also 49.
7^2 or 49.
Since 7^2 is 49 and 8^2 is 64, And the numbers must have a square root between 7 and 8, The numbers have to be in between 49 and 64. This is because if the numbers are under 49, Its square root will be below 7. And if the numbers are above 64, Its square root will be above 8.