First approximation by
estimated guess: x1 = 4
Better approximation:
x2 = x1 - [ (x12-15) / (2x1) ]
caculated: x2 = 4 - (16-15)/(8)= 3.87(50)
Even better approximation:
x3 = x2 - [ (x22-15) / (2x2) ]
caculated: x3 = 3.875 - (3.8752-15)/(2*3.875) = 3.87(2983(87096774))
Even more better approximation:
x4 = x3 ...... etc.
caculated: x4 = 3.872983(34620745)
Each time you replace x2 with x1 and repeat the equation many times until you get two answers with enough digits that are the same.
In this example you need to repeat the procedure
x2,round(2) = x3,round(2) = 3.87 , (between 3.875and 3.873)
or
x3,round(6) = x4,round(6) = 3.872983 , (between 3.8729839 and 3.8729833)
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The fourth root of fifteen raised to the third power is 7.622 (rounded).
There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)
A principal square root is any square root that's answer is positive, and a perfect square root is a square root that's answer is an integer.
square root of 20 = square root of 4 * square root of 5. square root of 4 = 2, so your answer is 2 square root of 5.
Square root (24) - square root (6) = 2.44948974