The answer is 2 on the square root of 3, all divided by 4. You come to this conclusion by multiplying the square root of three quarters by the square root of four divided by the square root of four, since there can't be a square root in the denominator. This will cancel out the "4" in the square root of three quarters, causing it to be now the square root of 12 over a normal four (the square root of four times the square root of four equals four). Then you simplify the square root of twelve by taking it's radical form, knowing that it takes 4 and 3 to multiply to get 12, and 4 is a perfect square, you take its perfect square which is 2, and put it outside of the square root of 3, all over 4. Hope this helped
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No, id does not.
The square root of six divided by the square root of two equals the square root of three.
Two times the square root of three plus five times the square root of three plus four times the square root of three equals eleven times the square root of three.
The square root of three-eighths to the nearest tenths place is 0.2
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