The square root of 81 is 9, and the square root of 49 is 7. Therefore, the square root of 81 over 49 can be expressed as (\sqrt{\frac{81}{49}} = \frac{\sqrt{81}}{\sqrt{49}} = \frac{9}{7}). So, the answer is (\frac{9}{7}).
The square root of -81 = 9 i9i
The square root of 81 is 9
The square root of 6561 is 81
9/13
Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36
To find the square root of a number you multiply that number by it self twice.(example) the square root of 9 ? the square root of nine is 81 as 9X9=81. square root of 4 ? th square root of is 16 as 4X4=16.
No. The square root of 81/(-3) is rational. The square root of [81/(-3)] is imaginary (a kind of complex number).
The square root of 81 is 9, and the square root of 49 is 7. Therefore, the square root of 81 over 49 can be expressed as (\sqrt{\frac{81}{49}} = \frac{\sqrt{81}}{\sqrt{49}} = \frac{9}{7}). So, the answer is (\frac{9}{7}).
They are 4 and 9 respectively
81 is the square root and 9.5 is under root.
sqrt(25/81) = 5/9
The square root of -81 = 9 i9i
The square root of 81 is 9
The square root of -81 = 9 i9i
The square root of 6561 is 81
The square root of 81 is 9 and the square root of 4 is 2!