For 2 6 1 4 2 2 4 3 2: σ=1.5366
2√(17/21), or about 1.8.
Consider thatxd= x- Arithmetic meand211-1.5 = -0.50.2522-1.5 = 0.50.25=0.5Arithmetic mean = (1+2)/2 =1.5Standard deviation=ie .5= 0.70now Considerxd= x- Arithmetic meand211-2=-1122-2=0033-2=11Arithmetic mean= (1+2+3)/3 = 2 =2Standard deviation= = (2/2) = 1So the Standard deviation can increasenow Considerxd= x- Arithmetic meand211-1.25=-0.250.062522-1.25=0.750.562511-1.25=-0.250.062511-1.25=-0.250.0625Arithmetic mean= (1+2+1+1)/4= 1.25 = .75Standard deviation= = (0.75/4) = 0.4330So the Standard deviation can decreaseStandard deviation can either decrese or increase or remains the same
3.4163.4163.4163.416
For 1 2 2 3 4 5 5 5 5 6: σ=1.6865
Standard deviation is the square root of the mean. The mean for this set is (2 + 4 + 3 + 7)/4 = 16/4 = 4; the square root of this is 2.
For 2 6 1 4 2 2 4 3 2: σ=1.5366
Standard deviation is the square root of the variance. Since you stated the variance is 4, the standard deviation is 2.
1. establishment of standard 2. fixation of the standard 3. compairing actual performance with standard performance 4. finding out the deviation 5. correcting the deviation
Variance = 17.9047619 Standard Deviation = 4.23140188
2√(17/21), or about 1.8.
Absolute deviation from what?
For 1 4 and 7: σ=3
Consider thatxd= x- Arithmetic meand211-1.5 = -0.50.2522-1.5 = 0.50.25=0.5Arithmetic mean = (1+2)/2 =1.5Standard deviation=ie .5= 0.70now Considerxd= x- Arithmetic meand211-2=-1122-2=0033-2=11Arithmetic mean= (1+2+3)/3 = 2 =2Standard deviation= = (2/2) = 1So the Standard deviation can increasenow Considerxd= x- Arithmetic meand211-1.25=-0.250.062522-1.25=0.750.562511-1.25=-0.250.062511-1.25=-0.250.0625Arithmetic mean= (1+2+1+1)/4= 1.25 = .75Standard deviation= = (0.75/4) = 0.4330So the Standard deviation can decreaseStandard deviation can either decrese or increase or remains the same
3.4163.4163.4163.416
You can calculate standard deviation by addin the numbers of data that are together and dividing that number by the amount pieces of data.THAT IS TOTALLY INCORRECT.What was answered above was the calculation for getting an (mean) average.If you take five numbers for example 1, 2, 3, 4, 5 then the (mean) average is 3.But the standard deviation between them is 1.58814 and the variance is 2.5Also the population std. deviation will be 1.41421 and the population variance will be 2.see standard-deviation.appspot.com/
Any real value >= 0.