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The static pressure exerted by a column of water can be calculated using the formula ( P = \rho g h ), where ( \rho ) is the density of water (approximately 1000 kg/m³), ( g ) is the acceleration due to gravity (about 9.81 m/s²), and ( h ) is the height of the water column in meters. For 1000 feet (approximately 305 meters) of water, the static pressure would be around 3,000,000 pascals, or 30 bar (approximately 435 psi).

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3w ago

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What is the static pressure of 25' with a psi of 80?

To calculate the static pressure at a depth of 25 feet with a psi of 80, we need to consider that 1 psi corresponds to approximately 2.31 feet of water. Therefore, the pressure in feet of water at 80 psi is 80 psi × 2.31 feet/psi = 184.8 feet. At a depth of 25 feet, the static pressure would be the sum of the atmospheric pressure (typically 14.7 psi at sea level) and the pressure from the water column. In this case, the static pressure at 25 feet is approximately 80 psi, assuming the measurement is taken at that depth.


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