Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!
No, as this represents the sum of two 11th powers. There is a factorization of x^11+y^11; however it is lengthy. The sum is 10^22+1^22.
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
The sum of 11 and 11 is 22.
x + y = 15 x - y = 7
x + y = 39 x - y = 11 _________ 2x = 50 x = 25 y = 14
Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!
No, as this represents the sum of two 11th powers. There is a factorization of x^11+y^11; however it is lengthy. The sum is 10^22+1^22.
xy=-60 x+y=11 x=11-y (11-y)y=-60 x=11+4= 15 or x=11-15= -4 11y-y2+60=0 y= -4 or 15 so the answer is 15 and -4 or -4 and 15
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
x=335.79 y=244.21
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
y+3y-11=24 4y-11=24 4y=35 y=35/4 x=61/4
Sum the digits in the odd positions in the integer. Sum = XSum the digits in the even positions in the integer. Sum = YIf X - Y is a multiple (including negative or 0), then the given integer is divisible by 11.
The sum of 11 and 11 is 22.
x + y = 15 x - y = 7
x + y = 11 and x - y = 5. The y's cancel so you're left with 2x = 16. So x = 8. Plug x back in to one of the original equations to find y. 8 + y = 11. So y = 3. And 3 times 8 = 24.