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What is the sum of 127 39 and 262?
It is: 127+39+262 = 428
What is 127 divided by 20?
6.35
What is 127 - 20 percent?
127 - 20 percent = 101.6
What is negative 5 and 3 over 4 minus 6 and 7 over 20 equal?
-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10
Could you find the sum of all seven digit numbers that can be written using only ones and zeros?
If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128
