Q: What is the sum of 127 and 20?

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It is: 127+39+262 = 428

127 - 20 percent = 101.6

6.35

-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10

If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128

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It is: 127+39+262 = 428

6.35

127 - 20 percent = 101.6

-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10

If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128

The wrong answer.

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63 and 64

How about: 127+5 = 132

20

How about: 100+20+7 = 127 as one example

It will be quicker to try different powers of two, and seeing if the remainder is prime. 127 = 1 + 126, 126 isn't prime 127 = 2 + 125, 125 isn't prime 127 = 4 + 123, 123 isn't prime 127 = 8 + 119, 119 isn't prime 127 = 16 + 111, 111 isn't prime 127 = 32 + 95, 95 isn't prime 127 = 64 + 63, 63 isn't prime 127 < 128, so all the possibilities are exhausted. So, 127 can't be expressed as a sum of a prime and a power of two.