13 + 33 = 46
The sum of 18 and 15 is 33. 10+10=20 & 8+5=13. 20+13=33.
The numbers are 9, 11 and 13.
1 +1 + 2 + 3 + 5 + 8 + 13 = 33
66
To find 54 more than the sum of 12 and 33, first calculate the sum of 12 and 33, which is 45. Then, add 54 to this sum: 45 + 54 equals 99. Therefore, 54 more than the sum of 12 and 33 is 99.
The sum of 18 and 15 is 33. 10+10=20 & 8+5=13. 20+13=33.
They are 9, 11 and 13.
33/3 = 11 so the three are 9, 11 and 13
The numbers are 9, 11 and 13.
2x + 7 = 33 2x = 33 - 7 2x = 26 X = 26/2 X = 13
1 +1 + 2 + 3 + 5 + 8 + 13 = 33
33 = 9 + 11 + 13
33
66
To find 54 more than the sum of 12 and 33, first calculate the sum of 12 and 33, which is 45. Then, add 54 to this sum: 45 + 54 equals 99. Therefore, 54 more than the sum of 12 and 33 is 99.
33% of 13= 33% * 13= 0.33 * 13= 4.29
153 = 13 + 53 + 33 Also: 370 = 33 + 73 + 03 371 = 33 + 73 + 13 407 = 43 + 03 + 73 See the Related Links for "Exponentiated digit sums" to the bottom for more...