The probabilityof ROLLING a sum of 12 is 1/36 ( 1 in 6 for each die = 1/6 x 1/6 = 1/36) The probabilityof NOT ROLLING a sum of 12 is 35/36 ( 1 - 1/36)
1 and 7/12
The sum of the prime numbers from 1 to 12 is equal to 2 + 3 + 5 + 7 + 11 = 28.
1/3 + 3/4 = 4/12 + 9/12 = 13/12 = 1 and 1/12
3/6 = 1/2, 12/12 = 1 So their sum is 1 1/2
W(1 + 1)
9
The sum of 5/12 and 2/3 is 1 1/12The sum of 5/12 and 2/3 is 1 1/12
15 + w expresses the sum of 15 and w
The sum of 1/6 and 1/4 is 5/12
If the question is - the sum of 1/6, 2/3 and 1/4 then the answer is; 13/12, or 1 1/12.
The probabilityof ROLLING a sum of 12 is 1/36 ( 1 in 6 for each die = 1/6 x 1/6 = 1/36) The probabilityof NOT ROLLING a sum of 12 is 35/36 ( 1 - 1/36)
A dozen is equal to 12. The sum of the digits of 12 are 1 + 2 = 3.
12
UtilityRT w (w, a) = 1/(i2wPRTw(i, ai))
1 and 7/12
1 and 12