The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
With 2 dice, there are 36 outcomes Of those, a sum of 5 can be made in 4 ways (1 + 4, 2 + 3, 3 + 2, 4 + 1) ⇒ pr(5) = 4/36 = 1/9 ≈ 0.11 ≈ 11 %
The sum of all numbers between 1 and 5 is infinite.The sum of whole numbers between 1 and 5 is 2 + 3 + 4 = 9
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
(2-5)+(2-4)=-1
It is 1 - Pr(rolling a sum of 5 with two dice) = 1 - Pr(1+4 or 2+3 or 3+2 or 4+1) = 1 - 4/36 = 8/9
Factors of 20 are 1, 2, 4, 5, 10 and 20. And their sum is 1 + 2 + 4 + 5 + 10 + 20 = 32.
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
Simple. You square the numbers and then calculate their sum - precisely as the name suggests.So the answer is 1^2 + 4^2 + 2^2 + 5^2 = 1 + 16 + 4 + 25 = 46
1+1+1+2=5
With 2 dice, there are 36 outcomes Of those, a sum of 5 can be made in 4 ways (1 + 4, 2 + 3, 3 + 2, 4 + 1) ⇒ pr(5) = 4/36 = 1/9 ≈ 0.11 ≈ 11 %
The sum of all numbers between 1 and 5 is infinite.The sum of whole numbers between 1 and 5 is 2 + 3 + 4 = 9
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.
The probability of rolling a sum of 5 with two dice is 4 in 36, or 1 in 9, or about 0.1111. 1 and 4 2 and 3 3 and 2 4 and 1
If 1,2,3,4,5, is a sequence, then the sum is 1+2+3+4+5 = 15