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∙ 13y ago(-5)*(-4) / [(-7) + 2] = (-5)*(-4)/(-5) = (-4) or -4.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.
The sum of the first 5 numbers is 15. 1+2+3+4+5=15
5 Check the intensity of the object. The sum will be 5.
(2-5)+(2-4)=-1
find the sum and product of the roots of 8×2+4×+5=0
Factors of 20 are 1, 2, 4, 5, 10 and 20. And their sum is 1 + 2 + 4 + 5 + 10 + 20 = 32.
Simple. You square the numbers and then calculate their sum - precisely as the name suggests.So the answer is 1^2 + 4^2 + 2^2 + 5^2 = 1 + 16 + 4 + 25 = 46
If 1,2,3,4,5, is a sequence, then the sum is 1+2+3+4+5 = 15
The sum of 5/7 and 2/4 is 1 3/14
The probability of rolling a sum of 8 with two dice is 5 in 36 or about 0.1389. 2 and 6 3 and 5 4 and 4 5 and 3 6 and 2
1+4=5 2+3=5 3+2=5 4+1=5 5+0=5
the sum is example 2+2=4, 4 is the sum
It is 1 - Pr(rolling a sum of 5 with two dice) = 1 - Pr(1+4 or 2+3 or 3+2 or 4+1) = 1 - 4/36 = 8/9
Factors for 20 are: 1, 2, 4, 5, 10, 20 Prime Factors: 2, 5 sum of prime factors = 2 + 5 = 7