If the question is, "What two numbers sum to 37 and have a difference of 3?"
Then the answer is 20 and 17
To solve the problem, call the two numbers a and b.
Then a + b = 37 therefore b = 37 - a.
And a - b = 3 : substitute the value (shown above) for b in this equation.
a - (37 - a) = 3 : 2a - 37 = 3 : 2a = 3 + 37 = 40 : a = 20
As a + b = 37 then 20 + b = 37 : b = 37 - 20 = 17
-4 + 7 = 37 - -4 = 11-4 and 7
37 and 45
First, calculate the sum of 37 and 45, which is 82. Then, to find trice that sum, multiply 82 by 3, resulting in 246. Therefore, the number that is trice the sum of 37 and 45 is 246.
They are: 29+5+3 = 37
2 and 1 .their sum is 3 .difference is 1
-4 + 7 = 37 - -4 = 11-4 and 7
37 + 29 = 66 37 - 29 = 8
37 and 45
16 and 21
That would be 24 and 61, sum: 24+61=85 and 61-24=37
3 + 2 = 5. (sum) 3 - 2 = 1. (difference)
10 and 5
It is: 3 times (37+45) = 246
3, 7 and 37
29, 5 and 3
3 and 9 Difference: 9-3=6 Sum: 9+3=12
difference: The sum of 5 and 3 is 8. The difference is 2.