The given sequence is an arithmetic progression with common difference d = 4 and first term a = 3.
Sum of n terms of an A.P. is given by: Sn = n/2 x [2a + (n-1)d]
We need to find sum of 11 terms so n = 11.
Putting value of n, a and d we get:
S11 = 11/2 x [2x3 + (11 - 1) x 4]
S11 = 11/2 x [6 + 40]
S11 = 11/2 x 46 = 11 x 23 = 253
To find the sum of the numbers 9, -11, and 15, you add them together: (9 + (-11) + 15). First, (9 - 11 = -2). Then, (-2 + 15 = 13). Therefore, the sum is 13.
No it doesn't. That sum is 100.
3 + 11 + 11 + 11 + 12 + 13 + 15 + 15 + 16 + 17 + 19 = 143
11
The total sum is 110
The sum of addends 11 and 15 is: 11 + 15 = 26
15 x 11
(5 x 15) + (6 x 15) = 11 x 15 = 165
The sum of 24, 15, 18, 18, 11, 25, 27, and 22 is 160. The addition process involves combining the individual values by adding them together. In this case, adding the numbers sequentially results in a total sum of 160.
To find the sum of the numbers 9, -11, and 15, you add them together: (9 + (-11) + 15). First, (9 - 11 = -2). Then, (-2 + 15 = 13). Therefore, the sum is 13.
Expressed as a proper fraction in its simplest form, 1/3 + 2/5 = 11/15 or eleven fifteenths.1/3 + 2/55/15 + 6/1511/155/15 + 6/15 = 11/15
They sum up to 15
No it doesn't. That sum is 100.
3 + 11 + 11 + 11 + 12 + 13 + 15 + 15 + 16 + 17 + 19 = 143
11
the sum of -14 + 29 is 15
11+4=15