The given sequence is an arithmetic progression with common difference d = 4 and first term a = 3.
Sum of n terms of an A.P. is given by: Sn = n/2 x [2a + (n-1)d]
We need to find sum of 11 terms so n = 11.
Putting value of n, a and d we get:
S11 = 11/2 x [2x3 + (11 - 1) x 4]
S11 = 11/2 x [6 + 40]
S11 = 11/2 x 46 = 11 x 23 = 253
3 + 11 + 11 + 11 + 12 + 13 + 15 + 15 + 16 + 17 + 19 = 143
No it doesn't. That sum is 100.
11
The total sum is 110
(-15) + 23 = 8
The sum of addends 11 and 15 is: 11 + 15 = 26
15 x 11
(5 x 15) + (6 x 15) = 11 x 15 = 165
The sum of 24, 15, 18, 18, 11, 25, 27, and 22 is 160. The addition process involves combining the individual values by adding them together. In this case, adding the numbers sequentially results in a total sum of 160.
They sum up to 15
Expressed as a proper fraction in its simplest form, 1/3 + 2/5 = 11/15 or eleven fifteenths.1/3 + 2/55/15 + 6/1511/155/15 + 6/15 = 11/15
3 + 11 + 11 + 11 + 12 + 13 + 15 + 15 + 16 + 17 + 19 = 143
No it doesn't. That sum is 100.
the sum of -14 + 29 is 15
11
11+4=15
15