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The given sequence is an arithmetic progression with common difference d = 4 and first term a = 3.

Sum of n terms of an A.P. is given by: Sn = n/2 x [2a + (n-1)d]

We need to find sum of 11 terms so n = 11.

Putting value of n, a and d we get:

S11 = 11/2 x [2x3 + (11 - 1) x 4]

S11 = 11/2 x [6 + 40]

S11 = 11/2 x 46 = 11 x 23 = 253

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13y ago

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