Two
The sum of two "V"s (Fives) are represented by one "X" (Ten), and the sum of two "L"s (Fifty) are represented by one "C" (Hundred).
TEN
32
3/5 = 0.6
Two
The sum of two "V"s (Fives) are represented by one "X" (Ten), and the sum of two "L"s (Fifty) are represented by one "C" (Hundred).
3 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 600
TEN
6
To solve this problem, we first calculate the sum of 2 tens and 10 twos: 2 tens = 20, 10 twos = 20, so the sum is 20 + 20 = 40. Next, we determine how many fives are equal to 40 by dividing 40 by 5, which equals 8. Therefore, there are 8 fives that have the same value as the sum of 2 tens and 10 twos.
12 and 3 10 and 5 three fives five threes fifteen ones
Because 10 is two fives so anything times ten is double as many fives.
32
The product is 15
3/5 = 0.6
The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0