10 + 3*5 = 10+15 = 25
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∙ 14y agoTwo
The sum of two "V"s (Fives) are represented by one "X" (Ten), and the sum of two "L"s (Fifty) are represented by one "C" (Hundred).
TEN
32
3/5 = 0.6
Two
The sum of two "V"s (Fives) are represented by one "X" (Ten), and the sum of two "L"s (Fifty) are represented by one "C" (Hundred).
3 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 600
TEN
6
8 (sum means add 2x10 +10x2 =40 then divide by 5 to find the amount of fives that fit=8)
12 and 3 10 and 5 three fives five threes fifteen ones
ten 50 / 5 = 10
Because 10 is two fives so anything times ten is double as many fives.
32
The product is 15
The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0