5050
1 + 2 + 3 + . . . . + 99 + 100 = ?
Arrange the numbers to add them like this:
(1 + 100) + (2 + 99) + (3 + 98) + . . . . + (50 + 51) = ?
If you notice every pair of numbers adds up to 101. There are 50
pairs of numbers, so the answer is 50*101 = 5050.
In general to find the sum of all the numbers from 1 to N:
1 + 2 + 3 + 4 + . . . . + N = (1 + N)*(N/2)
That is "1 plus N quantity times N divided by 2."
Hope this helps.
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Their sum is 10000.
44
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
This is the way I would do it: The sum of the 1st & 100th numbers = the sum of the 2nd & 99th numbers = the sum of the 3rd & 98th numbers all the way to the sum of the 50th & 51st numbers; each of the sums equals 200. So I would multiply 200 by 50 (10000).
the sum of the digits one hundred and twenty six is 9!!