It could be: (4*8)+(9-6) = 35
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
The sum is 22 times the sum of the three digits.
Possibility of two digit no whose sum is 8 17,26,35,44,53,62,71 Add 18 with above no each output will be 35,44,53,62,71,80,89 See after second comma 35 and 53. If you add 18 with 35. 53 will come if you reverse it 35. 35 is
the sum of my digits is 6? answer=60
It could be: (4*8)+(9-6) = 35
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
The sum is 22 times the sum of the three digits.
The sum of all the digits of all the positive integers that are less than 100 is 4,950.
Possibility of two digit no whose sum is 8 17,26,35,44,53,62,71 Add 18 with above no each output will be 35,44,53,62,71,80,89 See after second comma 35 and 53. If you add 18 with 35. 53 will come if you reverse it 35. 35 is
35
1000000
The sum of all the integers between 1,000 and 2,000 is 1,498,500.
When the sum of the digits you are adding is 10 or larger.
100
It is 45.
the sum of my digits is 6? answer=60