The given series is: 1, 3, 5, 7, 9,... 49. The series is an Arithmetic Progression because the difference between any two consecutive terms is 2(a constant).
In this A.P. first term(a) = 1, last term(l) = 49 and common difference(d) = 2.
nth term of an A.P. is given by an = a + (n-1)d
49 = 1 + (n-1)x2
48 = (n-1)x2
n-1 = 24
n = 25
So there are 25 terms in this A.P.
Sum of n terms of an AP is given by:
Sn = n/2 x (a + l)
S25 = 25/2 x (1 + 49)
S25 = 25/2 x 50
S25 = 25 x 25
S25 = 625.
So sum of odd numbers from 1 to 49 is 625.
The sum of 5 odd numbers must be odd and 100 is even. So there cannot be such a set.
If you mean sum, then 49 and 51!
The numbers are 45, 47, and 49.
49 and 51
It is not possible for five odd numbers to add up to 50 or any even number.
1 + 3 + 5 + ... + 49 = ((49 + 1)/2)2 = 625
49
the answer is 49.
The sum of 5 odd numbers must be odd and 100 is even. So there cannot be such a set.
If you mean sum, then 49 and 51!
49 is an odd number. All numbers ending in 1, 3, 5, 7, or 9 are odd numbers.
50 and 52 are the even numbers in this range, the odd numbers will be all the others, which is just the number 51.
The numbers are 45, 47, and 49.
49 and 51
147 / 3 = 49 49 will be the center number, just add and subtract 2 to/from 49 and you get 47+ 49 + 51 = 147
It is not possible for five odd numbers to add up to 50 or any even number.
49+51=100 49 is the smaller number : P