Four times the unknown number.
Let's say the unknown number is x.
x + 3x = 4x
450N, where "N" represents the unknown number.
The equation can be expressed as: ( 9 - 3x = 5(y + 5) ), where ( x ) is the unknown number being decreased and ( y ) is the unknown number being summed with five. This states that nine decreased by three times ( x ) is equal to five times the sum of ( y ) and five.
Their sum is three times the middle number.
The answer is 1. 5 times x - x < 5 + x It has to be 1, anything over 1 could not be less than.
Five
450N, where "N" represents the unknown number.
x + x - 3 = 2x - 3
The sum of three times a number and its square is 10 more than 6 times a number?
Their sum is three times the middle number.
Statement:The sum of three times of a number and five.Assumption:Let us take the number be x.So, Three times the number = 3x.Equation: 3x+5
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
3x+5x
The answer is 1. 5 times x - x < 5 + x It has to be 1, anything over 1 could not be less than.
Opposite of the sum is not a mathematical expression and I can only assume it means the difference.So,5x - x < |x - 5|Or 4x
-3
Five
Is this exactly how the problem was written?