Algorithm to find the sum and average of 3 numbers: Start. Input three numbers (let's call them A, B, and C). Calculate the sum (Sum = A + B + C). Calculate the average (Average = Sum / 3). Output the sum and average. End. Flowchart: [Start] ↓ [Input A, B, C] ↓ [Sum = A + B + C] ↓ [Average = Sum / 3] ↓ [Output Sum, Average] ↓ [End]
3+c
"the same as the others added together" For example: a=b+c+d a is equal to the sum of b plus c plus d. 9=2+3+4
c + n
The algorithm to find the sum and average of three numbers involves the following steps: Input three numbers (let's call them A, B, and C). Calculate the sum by adding the three numbers: Sum = A + B + C. Calculate the average by dividing the sum by 3: Average = Sum / 3. Output the sum and average. In a flowchart, you would start with a "Start" symbol, followed by input steps for the three numbers, then a process step for calculating the sum, another for calculating the average, and finally an output step to display the results before ending the flowchart.
Algorithm to find the sum and average of 3 numbers: Start. Input three numbers (let's call them A, B, and C). Calculate the sum (Sum = A + B + C). Calculate the average (Average = Sum / 3). Output the sum and average. End. Flowchart: [Start] ↓ [Input A, B, C] ↓ [Sum = A + B + C] ↓ [Average = Sum / 3] ↓ [Output Sum, Average] ↓ [End]
3+c
1.Start 2. Input a,b,c 3. Sum = a+b+c 4. Average = sum/3 5. Output - Sum,Average 6. Stop
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
matrix
Sum means to add.. so the equation would look like 3(c+d) or (c+d)*3. You could also add them separately. 3c+3d Hope that helps!
Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.
The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.
"the same as the others added together" For example: a=b+c+d a is equal to the sum of b plus c plus d. 9=2+3+4
J C Sum was born in 1976.
As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
To solve for the sum of the first n number of cubes, use (1+2+3+4+5...+n)2. So for n=100, (1+2+3+4+5...+100)2 = c (cubes) (101 * 50)2 = c 50502 = c c = 25502500