95
eight 10's (80)
three5s (15)
80 plus 15 is 95
1 − (2 × 10 + 8 × 5) = -59
eight
The largest three-digit number with a digit sum of 10 is 910. This can be determined by maximizing the hundreds place first, setting it to 9, and then adjusting the tens and units places to reach a total digit sum of 10. In this case, using 1 for the tens place and 0 for the units place achieves the desired sum.
eleven and three fourths
93
To solve this problem, we first calculate the sum of 2 tens and 10 twos: 2 tens = 20, 10 twos = 20, so the sum is 20 + 20 = 40. Next, we determine how many fives are equal to 40 by dividing 40 by 5, which equals 8. Therefore, there are 8 fives that have the same value as the sum of 2 tens and 10 twos.
1 − (2 × 10 + 8 × 5) = -59
-5 what is the sum of negative eight and three?
eight
11
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i
803
6
96
The largest three-digit number with a digit sum of 10 is 910. This can be determined by maximizing the hundreds place first, setting it to 9, and then adjusting the tens and units places to reach a total digit sum of 10. In this case, using 1 for the tens place and 0 for the units place achieves the desired sum.
eleven and three fourths
12 and 3 10 and 5 three fives five threes fifteen ones