118
6 + 18 + 20 = 44
The sum of 18 and 15 is 33. 10+10=20 & 8+5=13. 20+13=33.
(b+5)
Assuming that a and b are two non-negative numbers, then their sum is a + b and the difference is |a - b|.
18 + d
118
13, 3, and 2
6 + 18 + 20 = 44
Eighteen
4*m/5 + 18
4m/5 + 18
int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }
a/b+5=18
The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.
Consecutive even numbers that sum to thirty-eight (38) are eighteen (18) and twenty (20). Twenty (20) is larger than eighteen (18).
9+9= 18 If that is what you mean