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3240o.

The sum of the interior angles of a n sided polygon is

sum = (n - 2) x 180o

An icosagon has 20 sides, thus the sum of its interior angles is:

sum = (20 - 2) x 180o

= 3240o

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13y ago

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7y ago

An icosagon is a 20 sided polygon and its 20 interior angles add up to 3240 degrees

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7y ago

It is 3240 degrees.

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Q: What is the sum of interior angles icosagon?
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Related questions

What number is icosagon?

Icosagon is the TWENTY-sided Polygon ...... The sum of its interior angles = 3240 degrees


What is the sum of inerior angles of icosagon?

An icosagon is a 20 sided polygon and its interior angles add up to 3240 degrees


What is the formula for icosagon?

For a regular icosagon (20-sided polygon), the formula to calculate the sum of its interior angles is (n-2) * 180 degrees, where n is the number of sides. So, for an icosagon, the sum of its interior angles can be calculated as (20-2) * 180 = 3240 degrees.


What is the sum of interior angles of a icosagon?

That will depend on what type of isogon it is because an isogon is the name given to any regular polygon whose interior angles are equal.But in the general: (n-2)*180 = sum of interior of any polygon whereas 'n' is the number of sides of the polygon.


How many degrees in a 20 sided shape?

The sum of the interior angles of an icosagon is 3240 degrees, each angle of a regular icosagon being 162 degrees. * The formula for the sum of an n-sided polygon is 180 (n-2). 180 x 18 = 3240


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