The sum of the measures of the exterior angles of an octagon (and any polygon) is 360o.
6
It depends on what type of polygon it is and how many angles it has.
The sum of the internal angles of a polygon of n sides is (n-2)*180 degrees.
The sum of the exterior angles in any polygon is 360 degrees.Therefore that polygon is a decagon.
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
360 degrees. The sum of the measures of the exterior angles of any polygon is 360°.
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
The sum of the measures of the exterior angles of an octagon (and any polygon) is 360o.
If each angle measures 90 degrees the polygon is a square and so its angles sum to 360 degrees.
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
6
It depends on what type of polygon it is and how many angles it has.
sum of angles of polygon = 180(n-2) = 180*15 = 2700
The sum of the internal angles of a polygon of n sides is (n-2)*180 degrees.
The sum of the exterior angles in any polygon is 360 degrees.Therefore that polygon is a decagon.
The sum of the angles is 900 degrees - and the polygon does not need to be convex.