The sum is negative 8.
-8, -10 and -12.
The sum of 8 and 2 is 10
(-8) x (-2) = 16 (-8) + (-2) = -10 The two numbers are therefore -8 and -2.
The integers are -12, -10 and -8.
It is an algebraic equation.
The answer is -10 and -8. -8 + -10= -18 -8x-10 =80.
The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0
-10 + -8 = -18 -10 x -8 = 80 The two numbers are therefore -10 and -8.
The sum is negative 8.
-8, -10 and -12.
The sum of 8 and 2 is 10
(-8) x (-2) = 16 (-8) + (-2) = -10 The two numbers are therefore -8 and -2.
-20
The integers are -12, -10 and -8.
It is the negative of the sum of the two positive equivalents. For example, (-5) + (-8) = -[5 + 8] = -13
-8, -9, -10, -11