The sum of one sixth, when considered alone, is simply ( \frac{1}{6} ). If you're asking for the sum of multiple sixths, such as "the sum of one sixth added to itself," that would be ( \frac{1}{6} + \frac{1}{6} = \frac{2}{6} ), which simplifies to ( \frac{1}{3} ).
The sum is 5/18
The sum is 1 5/12
The sum is 11/12
The sum is -5/6
One sixth of the sum of a number (let's call it ( x )) and three can be expressed mathematically as ( \frac{1}{6}(x + 3) ). This means you first add the number to three, and then divide the result by six.
The sum is 5/18
The sum is 5/18
The sum is 1 5/12
The sum is 23/30
60
The sum is 11/12
The sum is -5/6
The sum of 1/6 and 1/8 is 7/24
No it is not.
(a+b)/6
One sixth of the sum of a number (let's call it ( x )) and three can be expressed mathematically as ( \frac{1}{6}(x + 3) ). This means you first add the number to three, and then divide the result by six.
The sum of 1/6 and 5/7 is 37/42