The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
1010111 1111100 1011101 and many more
That would be an addition problem such as 2+3=5 5 would be the sum.
The sum of divisors of a number, excluding the number itself, is called its aliquot sum
No odd number of odd numbers can sum to an even number.
The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
5 x (6 + n)
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
And the sum of 5..? Uhh... Is it 5?
0.8333
There are no 5 odd numbers whose sum is 50. (The sum of 5 odd numbers is an odd number whereas 50 is an even number.)
5x + 6
1010111 1111100 1011101 and many more
five times the sum of a number and 8 is -15.
The sum of 8 and 5 is 13. There is then no number with which to calculate its product.
The 5th prime number is 11, and the 5th Fibonacci number is 5.The sum will be 11 + 5 = 16
Find the sum of the first hundred even natural number divisible by 5?