Q: What is the sum of the degrees of the internal angles of a tetradecagon?

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The sum of the internal angles of any regular polygon can be determined by 180 x (n - 2), where n is the number of sides. In this instance, since a tetradecagon has 14 sides, the sum of the internal angles is equal to 180 x (14 - 2) = 180 x 12 = 2160 degrees. Dividing this by the number of sides gives us the number of degrees in each one of the angles. In this instance, 2160 / 14 = 154 and two sevenths, or 154.285714 recurring degrees.

180 degrees

The internal angles add to 180 degrees.

The sum of the internal angles of a pentagon is 540 degrees.

Assuming you meant 'internal' angles - a hexagon.

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The sum of the internal angles of any regular polygon can be determined by 180 x (n - 2), where n is the number of sides. In this instance, since a tetradecagon has 14 sides, the sum of the internal angles is equal to 180 x (14 - 2) = 180 x 12 = 2160 degrees. Dividing this by the number of sides gives us the number of degrees in each one of the angles. In this instance, 2160 / 14 = 154 and two sevenths, or 154.285714 recurring degrees.

The sum of the internal angles of any regular polygon is (n - 2) x 180 degrees. Since a triacontakaihexagon has 36 sides, the sum of the internal angles of a triacontakaihexagon has a sum of internal angles of (36 - 2) x 180 = 6120 degrees.

The sum of the internal angles of any triangle is 180 degrees. Any rectangle has four 90 degree internal angles, totalling 360 degrees.

the sum of the internal angles is 540 degrees

360 degrees

180 degrees

The internal angles add to 180 degrees.

Each angle is 120 degrees. Six vertices multiplied by 120 degrees each gives you 720 degrees as the sum of the internal angles.

720 degrees

360 degrees.

The sum of the internal angles is 180*(11 - 2) = 180*9 = 1620 degrees. The sum of the external angles is 360 degrees - irrespective of the number of sides.

The sum of the internal angles of a pentagon is 540 degrees.