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What is the sum of the exterior angle measure of a regular decagon?
For any polygon, regular or otherwise, the sum of exterior angles is always 3600.
What is the size of each interior angle of a regular decagon?
A ten-sided polygon. The sum of the angles of a decagon is 1440°. so 1440°÷10=144° ---------------------------------------------------------------------------- The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular decagon is 360° ÷ 10 → Each interior angle of a regular decagon = 180° - 360° ÷ 10 = 144°
The sum of the exterior angle measure of a regular decagon is?
Each exterior angle measures 36 degrees and the 10 exterior angles add up to 360 degrees.
What is the measure of one exterior angle of a regular decagon?
36oFor all polygons, the sum of the exterior angles is 360o.For a regular polygon they are all the same thus:exterior_angle = 360o ÷ number_of_sidesSo for a decagon with 10 sides this becomes:exterior_angle = 360o ÷ 10= 36oIt is 36 degrees
What would be the sum of the exterior angle measures of a regular decagon?
For any polygon, whether it is regular or irregular (even concave), the sum of the exterior angles is always 360 degrees. -- WRONG, the answer is 1440 degrees. The sum is equal to (number of sides-2)*180, I believe.
