2+4+6+8+10........+40=420
110
The sum of the first 20 even numbers... is 110
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
To find the sum of all even numbers between 10 and 20, we first need to identify the even numbers in that range. The even numbers between 10 and 20 are 10, 12, 14, 16, and 18. Adding these numbers together, we get 10 + 12 + 14 + 16 + 18 = 70. Therefore, the sum of all even numbers between 10 and 20 is 70.
110
The sum of the first 20 even numbers... is 110
var sum = 0; for (var i = 0; i < 20; i++) { sum = sum + i * 2; }
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
To find the sum of all even numbers between 10 and 20, we first need to identify the even numbers in that range. The even numbers between 10 and 20 are 10, 12, 14, 16, and 18. Adding these numbers together, we get 10 + 12 + 14 + 16 + 18 = 70. Therefore, the sum of all even numbers between 10 and 20 is 70.
The answer is 20*20 = 400
well, let's break it down. First, the even numbers between 1 and 11 are, 2,4,6,8,10. Now 2+4=6, 6+6=12, 8+12=20, 20+10=30. So, to answer your question simply, the sum of even numbers between 1 and 11, is 30.
50
It is 155 greater.
It is impossible to add eight odd numbers together to get an even sum like 20. The sum of any odd numbers is always odd if an odd count of them is used, and it becomes even only when an even count is used. Since eight is an even number, the sum of eight odd numbers would be even, but it will still exceed 20 since the smallest odd number is 1, and the sum of eight 1s is 8, which is less than 20. Thus, there are zero ways to add eight odd numbers to achieve a sum of 20.
210