2+4+6+8+10........+40=420
110
The sum of the first 20 even numbers... is 110
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The even numbers less than 20 are 2, 4, 6, 8, 10, 12, 14, 16, and 18. To find the sum, you can use the formula for the sum of an arithmetic series: ( n/2 \times (first\ term + last\ term) ). Here, there are 9 even numbers, so the sum is ( 9/2 \times (2 + 18) = 9/2 \times 20 = 90 ). Thus, the sum of all even numbers less than 20 is 90.
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
110
The sum of the first 20 even numbers... is 110
var sum = 0; for (var i = 0; i < 20; i++) { sum = sum + i * 2; }
To write a program in QBasic that prints the sum of the even numbers from 1 to 20 in reverse order, you can follow these steps: DIM sum AS INTEGER sum = 0 FOR i = 20 TO 2 STEP -2 sum = sum + i NEXT i PRINT "The sum of even numbers from 1 to 20 is: "; sum This program initializes the sum to zero, iterates from 20 down to 2 in steps of -2 (to capture even numbers), adds each even number to the sum, and finally prints the result.
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The even numbers less than 20 are 2, 4, 6, 8, 10, 12, 14, 16, and 18. To find the sum, you can use the formula for the sum of an arithmetic series: ( n/2 \times (first\ term + last\ term) ). Here, there are 9 even numbers, so the sum is ( 9/2 \times (2 + 18) = 9/2 \times 20 = 90 ). Thus, the sum of all even numbers less than 20 is 90.
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
To find the sum of all even numbers between 10 and 20, we first need to identify the even numbers in that range. The even numbers between 10 and 20 are 10, 12, 14, 16, and 18. Adding these numbers together, we get 10 + 12 + 14 + 16 + 18 = 70. Therefore, the sum of all even numbers between 10 and 20 is 70.
well, let's break it down. First, the even numbers between 1 and 11 are, 2,4,6,8,10. Now 2+4=6, 6+6=12, 8+12=20, 20+10=30. So, to answer your question simply, the sum of even numbers between 1 and 11, is 30.
The answer is 20*20 = 400
To calculate the sum of all even numbers starting from 20 until the sum exceeds 1000, you can initialize a variable for the sum and a counter starting at 20. In a loop, add the counter to the sum and increment the counter by 2 (to keep it even) until the sum exceeds 1000. The final sum will be the total of all even numbers added. Here's a simple pseudocode example: sum = 0 number = 20 while sum <= 1000: sum += number number += 2
The even numbers greater than 10 but less than 20 are 12, 14, 16, and 18. To find the sum, we add these numbers: 12 + 14 + 16 + 18 = 60. Therefore, the sum of the even numbers in that range is 60.