2+4+6+8+10........+40=420
110
The sum of the first 20 even numbers... is 110
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The even numbers less than 20 are 2, 4, 6, 8, 10, 12, 14, 16, and 18. To find the sum, you can use the formula for the sum of an arithmetic series: ( n/2 \times (first\ term + last\ term) ). Here, there are 9 even numbers, so the sum is ( 9/2 \times (2 + 18) = 9/2 \times 20 = 90 ). Thus, the sum of all even numbers less than 20 is 90.
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
110
The sum of the first 20 even numbers... is 110
var sum = 0; for (var i = 0; i < 20; i++) { sum = sum + i * 2; }
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The even numbers less than 20 are 2, 4, 6, 8, 10, 12, 14, 16, and 18. To find the sum, you can use the formula for the sum of an arithmetic series: ( n/2 \times (first\ term + last\ term) ). Here, there are 9 even numbers, so the sum is ( 9/2 \times (2 + 18) = 9/2 \times 20 = 90 ). Thus, the sum of all even numbers less than 20 is 90.
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
To find the sum of all even numbers between 10 and 20, we first need to identify the even numbers in that range. The even numbers between 10 and 20 are 10, 12, 14, 16, and 18. Adding these numbers together, we get 10 + 12 + 14 + 16 + 18 = 70. Therefore, the sum of all even numbers between 10 and 20 is 70.
The answer is 20*20 = 400
well, let's break it down. First, the even numbers between 1 and 11 are, 2,4,6,8,10. Now 2+4=6, 6+6=12, 8+12=20, 20+10=30. So, to answer your question simply, the sum of even numbers between 1 and 11, is 30.
The even numbers greater than 10 but less than 20 are 12, 14, 16, and 18. To find the sum, we add these numbers: 12 + 14 + 16 + 18 = 60. Therefore, the sum of the even numbers in that range is 60.
50
It is 155 greater.