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What is the sum of the measures of the interior angles of a regular polygon is each exterior angle measures 120?
To find the sum of the measures of the interior angles of a regular polygon with each exterior angle measuring 120 degrees, we first determine the number of sides in the polygon. The sum of exterior angles of any polygon is always 360 degrees, so the number of sides ( n ) can be calculated as ( n = \frac{360}{120} = 3 ). Since it is a triangle, the sum of the interior angles is given by the formula ( (n - 2) \times 180 ) degrees, which for a triangle (3 sides) is ( (3 - 2) \times 180 = 180 ) degrees. Thus, the sum of the measures of the interior angles is 180 degrees.
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One exterior angle of a regular polygon measures 36 What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 36. What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 30 degrees what is the sum of the polygon's interior angle measures?
1800 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90?
360
What is the sum of the measures of the interior angles of a regular of a regular polygon if each exterior angle measures 120?
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
What is the sum of the measures of the interior angles of the regular polygon if each exterior measures 120?
Hint: in a regular polygon interior plus exterior = 180o, always.
What is the sum of the measures of the interior of a regular polygon if each exterior angle measures 90?
360
One exterior angle of a regular polygon measures 36 What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 36. What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 30 degrees what is the sum of the polygon's interior angle measures?
1800 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90?
360
What is the sum of the measures of the interior angles of a regular of a regular polygon if each exterior angle measures 120?
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
What is the sum of the polygon's interior angle measures if the exterior angle of a regular polygon's 36 degree?
1440 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72?
540 degrees
What is the measures of an interior angle and an exterior angle of a regular polygon with 6 sides?
Interior angle = 120 degrees Exterior angle = 60 degrees
