13 6+7=13
I'm pretty sure, If I'm wrong, I hope not!......
the sum of six and one becuase that equals 7 and the product of six and one equals 6
6 and 7
The sum of 6 and 7 is found by adding the two numbers together, which equals 13. The product of 6 and 7 is found by multiplying the two numbers, which equals 42. Therefore, the difference between the two is 42 - 13 = 29.
No, you cannot always find the sum of the factors of a product just by knowing the product itself. For example, the product 6 can be factored into 2 and 3, which sum to 5. However, it can also be factored into 1 and 6, which sum to 7. Therefore, the sum of the factors varies depending on the specific factorization chosen.
Product = 35 Sum = 12
29.
Numbers that have a product of 8 are 1,8 and 2,4. Their sums are 9 and 6 respectively. Numbers that have a product of 7 and a sum of 8 are 1 and 7.
the sum of six and one becuase that equals 7 and the product of six and one equals 6
six, seven 7 + 6 = 13 (sum) 7 - 6 = 1 (difference) 7 x 6 = 42 (product)
6 & 1. 6+1=7 and 6X1=6
6 and 7
The sum of 6 and 7 is found by adding the two numbers together, which equals 13. The product of 6 and 7 is found by multiplying the two numbers, which equals 42. Therefore, the difference between the two is 42 - 13 = 29.
55
The math expression for the sum of 7 and -2 is 7 + (-2) = 5. The math expression for the product of -6 and -4 is (-6) * (-4) = 24. Therefore, the expression for the sum of 7 and -2 subtracted from the product of -6 and -4 is 24 - 5 = 19.
No, you cannot always find the sum of the factors of a product just by knowing the product itself. For example, the product 6 can be factored into 2 and 3, which sum to 5. However, it can also be factored into 1 and 6, which sum to 7. Therefore, the sum of the factors varies depending on the specific factorization chosen.
7 and 6
Product = 35 Sum = 12