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Since the cell has six sides, it must be a tetrahedron.

Area = sqrt(3)*32 mm2 = 9*sqrt(3) mm2

Volume = 33/(6*sqrt(2))

So area/Volume = 9*sqrt(3)*6*sqrt(2)/33 mm

= 2*sqrt(6) mm

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12y ago

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Q: What is the surface-area-to-volume ratio for a cell whose six sides are 3 mm long?
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