Since the cell has six sides, it must be a tetrahedron.
Area = sqrt(3)*32 mm2 = 9*sqrt(3) mm2
Volume = 33/(6*sqrt(2))
So area/Volume = 9*sqrt(3)*6*sqrt(2)/33 mm
= 2*sqrt(6) mm
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As size increases, the s/v ratio decreases-- the s/v ratio of a cubic cell 1mm on a side is 6, but the s/v ratio of a cubic cell 3mm on a side is only 2.
The larger the surface area to volume ratio of a cell, the smaller its size (and vice versa).
A small cell will have a larger surface-to-volume ratio.
... will decrease.
Look in the book broseff.