60 square feet
If a cube has sides of length x inches, its surface area is 6*x2 sq inches. So 6*x2 = 96 x2 = 16 so that x = 4 inches = 4/12 feet = 1/3 ft. Then the volume is (1/3)3 = 1/27 cubic feet.
Area of square = x2 where x is the length of each side. So x2 = 81 sq ft x = sqrt(81) ft = 9 ft
x2 - x10 + x5 - x12 - x3
Let the side length of the cube be x:- Surface area: 6*x2 = 726 square feet Divide both sides by 6 and then square root both sides. x = 11 feet Volume: 11*11*11 = 1331 cubic feet
add them all then divide by 4 then multiply x2
Approximately 96.4 bushels.
Forty, or a piece of lumber 2 in x2 in x10 ft long.
The surface area of the cube will be 54cm2To find the surface area for other cubes, take the edge length (x) and square it (x2) and then multiply that by six: x2*6 = surface area.
If a cube has sides of length x inches, its surface area is 6*x2 sq inches. So 6*x2 = 96 x2 = 16 so that x = 4 inches = 4/12 feet = 1/3 ft. Then the volume is (1/3)3 = 1/27 cubic feet.
Area of square = x2 where x is the length of each side. So x2 = 81 sq ft x = sqrt(81) ft = 9 ft
x2 - x10 + x5 - x12 - x3
x2 = (x - 4)(x + 5) x2 = x2 - 4x + 5x - 20 x = 20 The first room area = x2 = 202 = 400 ft2 The second room area = (x-4)(x+5) = 16 ft * 25 ft = 400 ft2
lw + lh + wh x2
The cheat codes are x2 FfAs23T x10 dof2vd2
this is incorrect -- quick example.. 2"x2"x2" cube -- will have a surface area on each side of 4"sq (2x2=4) --- now make that 4"x4"x4" -- this cube will have a surface area on each side of 16"sq (4x4=16)
Let the side length of the cube be x:- Surface area: 6*x2 = 726 square feet Divide both sides by 6 and then square root both sides. x = 11 feet Volume: 11*11*11 = 1331 cubic feet
add them all then divide by 4 then multiply x2