The area is the length times the width. The height is irrelevant for the area.
It depends on the size of the bricks and their orientation.
A=L(W) A= 10(3) A= 30ft2
The answer will depend on the size of the bricks.
372 square inches
The area is the length times the width. The height is irrelevant for the area.
the netball posts are 10ft high
It depends on the size of the bricks and their orientation.
28
A=L(W) A= 10(3) A= 30ft2
Assuming a rectangular prism. The surface area is 550 square inches.
The diagonal is 14.142 feet.
The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.
The answer will depend on the size of the bricks.
The volume of a 10ft container depends on its dimensions (length, width, and height). To calculate the volume, you would multiply the length by the width by the height. For example, if the container is 10ft long, 8ft wide, and 8ft high, the volume would be 640 cubic feet (10ft x 8ft x 8ft = 640 cubic feet).
If the tank is rectangular, then the area, as seen from above, is 10 x 70 = 700 sq.ft. That will be like the floor area of a long pool.If the tank is round, 10x70xpi or 3.14 plus another 100 sq ft for the top.The question said the tank was 70 long not high (like a 10ft. pipe on its side)If we assume that the tank is round and that the external surface area was required with both ends exposed and included, then the surface area will be:102 x Pi/4 x 2 ends = 78.54 sq.ft. each x 2 ends = 157.08 sq.ft. PLUS the cylindrical area which is Pi x 10 x 70 = 2199.115 sq.ft.Total surface area = 2356.195 sq.ft.
448