Assuming that the cylinder has no end caps then the surface area, A = 2πrh
Substituting the given dimensions then A = 2π x 11 x 11 = 760.27 in² (2dp).
If there are end caps then one these has an area of πr² so together they have an area of 2πr² = 2π x 11² = 760.27........so the combined area = 1520.54 in²
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Its complete surface area = (2*pi*radius squared)+(2*pi*radius*height) in square inches
A cylinder that has a radius of 5 inches and a height of 11 inches has a surface area of 502.65 inches2
The surface area of a cylinder with height of 12 inches and 7 inch radius is 835.66 square inches
The lateral surface area of a cylinder with a height of twelve inches and a radius of seven inches equals 527.79 square inches.
The total surface area is 2*pi*r*(r + h) square inches, where r is the radius and h is the height.