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Assuming that the cylinder has no end caps then the surface area, A = 2πrh

Substituting the given dimensions then A = 2π x 11 x 11 = 760.27 in² (2dp).

 

If there are end caps then one these has an area of πr² so together they have an area of 2πr² = 2π x 11² = 760.27........so the combined area = 1520.54 in²

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Q: What is the surface area of a cilynder that has a radius of 11 inches and a height of 11 inches?
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