It is: 6*9*9 = 486 square units
A regular tetrahedron, with edges of length 1 units, has a total surface area of sqrt(3) square units.
The surface area of the square: 5.5*5.5 = 30.25 square units
Each face is 25m2 and there are 6 faces...
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
Each side has surface area of 3X3 = 9 cm 6 sides X 9 cm/side = 54 cm
Surface area is measured in square units.
A regular tetrahedron, with edges of length 1 units, has a total surface area of sqrt(3) square units.
The surface area of the square: 5.5*5.5 = 30.25 square units
You square the length of each edge and then multiply the result by six. For example, if a cube has edges measuring 3cm, the surface area will be 32 (9) x 6 = 9 x 6 = 54 square units.
6*112 = 726 square inches
Each face is 25m2 and there are 6 faces...
A cube has six faces. Therefore, its surface area is 6 times a face's area.The area of a square whose edges measure 9 cm is 81 cm2.Therefore, the surface area of a cube whose edges measure 9 cm is 6*81 = 486 cm2.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
If the lengths of the edges are x, y and z units, then the total surface area is 2*(xy + yz + zx).
If the edges are of length L, B and H units, then the total surface area is 2*(L*B + B*H + H*L) square units.
Each side has surface area of 3X3 = 9 cm 6 sides X 9 cm/side = 54 cm
You always use square units when measuring area.