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There are two ends, each of area {pi}r2 and the side which can be worked out by cutting the cylinder down (from end to end) and unrolling; one length is the cylinder height (h), the other is the circumference of the end (2{pi}r), giving 2{pi}rh.

Area = 2x({pi}r2) + 2{pi}rh

Area ~= 2x3.14x112 + 2x3.14x11x11

Area ~= 1520.5in2

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Q: What is the surface area of a cylinder whose radius is 11 inches and whose height is 11 inches?
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