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The volume cannot be 162m since that is not a measure of volume. Assume the volume is 162 m3, instead.

Suppose the sides are 3s, 2s and s.

Then volume = 6s3 = 162 m3 so that s3 = 27 m3 and so s = 3 m.

So the sides are 9m, 6m and 3 m.

Surface area = 2*(3s*2s + 2s*s + s*3s) = 2*(6s2 + 2s2 + 3s2) = 22s2 = 22*9 = 198 m2.

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