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The tangent line to a straight line, such as y = 2x - 3, is the straight line, itself.

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What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Equation of circle: x^2 +y^2 -4x -8y -5 = 0 Completing the squares: (x-2)^2 +(y-4)^2 = 25 which is radius squared Center of circle: (2, 4) Tangent line originates from: (8, 2) Distance from (8, 2) to (2, 4) is sq rt of 40 which is hypotenuse of right angle triangle Using Pythagoras theorem: distance^2 minus radius^2 = 15 Therefore length of tangent line is the square root of 15


2x3 plus 3x5- 3x2 equals?

(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156


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What is the tangent of 15 degrees?

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What is the prime factorization of 6 and 15?

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What is the length of the tangent line from the point 8 2 to a point where it touches the circle of x2 plus y2 -4x -8y -5 equals 0 on the Cartesian plane?

The distance from (8, 2) to the center of the circle forms the hypotenuse of a right angle triangle with the circle's radius meeting the tangent line at right angles and so:- Equation of the circle: x^2 +y^2 -4x -8y -5 = 0 Completing the squares: (x-2)^2 +(y-4)^2 = 25 Center of circle: (2, 4) Radius of circle: 5 Distance from (8, 2) to (2, 4): 2 times square root of 10 Using Pythagoras' theorem: distance squared minus radius squared = 15 Therefore length of the tangent line is the square root of 15


What is the value of 2x3 plus 15y if x equals -7 and y equals 2?

If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656


A tangent segment and a secant segment are drawn to a circle from a point outside the circle. The length of the tangent segment is 15 inches. The external segment of the secant segment measures 5 inches. What is the measure of the internal secant segment?

Course Hero Question A tangent segment and a secant segment are drawn to a circle from a point outside the circle. The length of the tangent segment is 15 inches. The... Answer · 0 votes Length of interior part of secant = 40 inches Please see attached image for diagram with work shown Image transcriptions The tangent—secant theorem states that if a tangent and a secant are drawn from the same external point, the length of the tangent squared is equal to the external part of the secant multiplied by the whole segment. 15_ Let x = the length of the inner segment of the secant II'I ' Length whole secant = length interior of secant + length exterior of secant 5 in = x + 5 (tangent? = (length exterior) * (length whole secant) (15)2 = (5) * (x + 5) 225 = 5x + 25 200: 5x 40:): Measure of internal segment = 40 inches More


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