To find the third term of the sequence defined by the recursive rule ( f(1) = 2 ) and ( f(n) = f(n-1) + 1 ), we first calculate ( f(2) ) using the recursive formula. Since ( f(1) = 2 ), we have ( f(2) = f(1) + 1 = 2 + 1 = 3 ). Next, we calculate ( f(3) ) as ( f(3) = f(2) + 1 = 3 + 1 = 4 ). Thus, the third term of the sequence is ( f(3) = 4 ).
To find the 5th term of the sequence defined by the formula (2n + 3), substitute (n = 5) into the equation. This gives (2(5) + 3 = 10 + 3 = 13). Therefore, the 5th term of the sequence is 13.
A mathematical sequence is a list of numbers arranged in a specific order according to a defined rule. If we say the sequence is "equal," it typically refers to an arithmetic sequence, where the difference between consecutive terms is constant. In such sequences, each term can be expressed as the previous term plus a fixed value (the common difference). For example, in the sequence 2, 4, 6, 8, the common difference is 2, and each term is equal to the previous term plus 2.
Without an equality sign it is no kind of an equation at all.
32
It is not possible to give a conclusive answer because for a recursive relationship of order 1, the first (or 0th) term must be specified.A(n) = (5*n^2 + 3*n + 2*A(1) - 8)/2 for n = 1, 2, 3, ...
To find the 5th term of the sequence defined by the formula (2n + 3), substitute (n = 5) into the equation. This gives (2(5) + 3 = 10 + 3 = 13). Therefore, the 5th term of the sequence is 13.
A mathematical sequence is a list of numbers arranged in a specific order according to a defined rule. If we say the sequence is "equal," it typically refers to an arithmetic sequence, where the difference between consecutive terms is constant. In such sequences, each term can be expressed as the previous term plus a fixed value (the common difference). For example, in the sequence 2, 4, 6, 8, the common difference is 2, and each term is equal to the previous term plus 2.
Without an equality sign it is no kind of an equation at all.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
It means that each number in the sequence is formed from the previous number by adding d to it. So, 1, 1+d, 1+2d, 1+3d, etc or 4, 4+d, 4+2d, 4+3d, etc
void infinte (long l) { printf ("I will never stop #%ld\n", l); infinte (l+1); }
15
1/3 plus 2/3 plus 3/3 = two
The sequence is poorly defined. 1+3+5 appears to be a sequence of odd numbers. However, that cannot end in 100: it can attain the values of 99 or 101. Obviously the answer will depend on which one of these is the final number. An alternative is that the sequence is not that of odd numbers but some other sequence: for example, t(n) = (29n3 - 174n2 + 399n - 214)/40 which, for n = 1, 2, 3, generates the sequence 1, 3, 5, 11.35, 26.4, 54.5, 100 whose sum is 201
32
It is not possible to give a conclusive answer because for a recursive relationship of order 1, the first (or 0th) term must be specified.A(n) = (5*n^2 + 3*n + 2*A(1) - 8)/2 for n = 1, 2, 3, ...
1 whole, or 1