2.01 seconds.
Nice problem! I get 32.1 centimeters.
9.5 inches
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
25=side
length: 22.5
Nice problem! I get 32.1 centimeters.
9.5 inches
The pendulum length is the distance from the point of suspension to the center of mass of a pendulum. It affects the period of the pendulum's swing, with longer lengths typically resulting in longer periods. A longer pendulum length will generally have a slower swing compared to a shorter length.
Area = length x width Area = 100cm x 100cm Area = 10000cm2
the longer you make the pendulum arm the longer it will take to perform its swing,the same thing would happen if you only increased the weight on the end of the arm.
The period of oscillation of a simple pendulum displaced by a small angle is: T = (2*PI) * SquareRoot(L/g) where T is the period in seconds, L is the length of the string, and g is the gravitional field strength = 9.81 N/Kg. This equation is for a simple pendulum only. A simple pendulum is an idealised pendulum consisting of a point mass at the end of an inextensible, massless, frictionless string. You can use the simple pendulum model for any pendulum whose bob mass is much geater than the length of the string. For a physical (or real) pendulum: T = (2*PI) * SquareRoot( I/(mgr) ) where I is the moment of inertia, m is the mass of the centre of mass, g is the gravitational field strength and r is distance to the pivot from the centre of mass. This equation is for a pendulum whose mass is distributed not just at the bob, but throughout the pendulum. For example, a swinging plank of wood. If the pendulum resembles a point mass on the end of a string, then use the first equation.
Well, darling, the area of a square is calculated by multiplying the length of one side by itself. So, in this case, the area of a square with a side length of 100cm would be 100cm x 100cm, which equals 10,000 square centimeters. Voila!
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
25=side
The perimeter is 100cm
It is a square with lengths of 10 cm
175cm *1m/100cm =1.75m