Not sure what you mean, but there would be more than one. 12 is an example. 1+2 = 3, 12/3 = 4 and 12/1 = 12, 12/2 = 6
12
A three-digit number divisible by both 2 and 5 must end with a 0, as this is the only digit that satisfies both conditions. The smallest three-digit number is 100, and the largest is 999. Therefore, any three-digit number that ends in 0, such as 100, 110, or 990, is divisible by both 2 and 5.
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
A five-digit number that is divisible by both 9 and 4 must meet the criteria for divisibility by these numbers. A number is divisible by 9 if the sum of its digits is divisible by 9, and it is divisible by 4 if the last two digits form a number that is divisible by 4. The smallest five-digit number is 10,000, and the largest is 99,999; thus, any five-digit number that meets these criteria can be calculated by finding the least common multiple of 9 and 4, which is 36, and checking multiples of 36 within that range. For example, 10,008 is a five-digit number divisible by both 9 and 4.
27000
12
The least three-digit number that is divisible by both 5 and 9 is 135.
There are several. 12. Divisible by 3 and 2. 24 divisible by 8 and 6. 36 divisible by 18 and 9. There may be more LCKMA
A three-digit number divisible by both 2 and 5 must end with a 0, as this is the only digit that satisfies both conditions. The smallest three-digit number is 100, and the largest is 999. Therefore, any three-digit number that ends in 0, such as 100, 110, or 990, is divisible by both 2 and 5.
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
99,600 is the largest 5-digit number that meets both requirements.
How about: 108
54.
99999
27000
2400
54