9 and 4, respectively; the number will end in 49.
01.
Yes. One way is 3! + 5*7 + 9 = 6 + 35 + 9 = 50
1.798465e42
The greatest number formed by rearranging the digits is 97514. There are, however, much larger even number. For example, 954^71 is a number that is larger than googol squared. And 4^(71^95) is very much larger. <<>> 97541> 97514 . . . How about 4 to the power 5 to the power 7 to the power 91. Or how about 4! to the power 5! to the power 7! to the power 91!.
The unit digit of 3127173 is the unit digit of 7173. The other digits of 3127 are multiples of 10 and so they cannot contribute to the unit digit. Now the unit digits of the powers of 7 are Power -- Unit digit 0 -- 1 1 -- 7 2 -- 9 3 -- 3 4 -- 1 and you are back into the loop (of 1-7-9-3). So, you only need consider 7 to the power 173 modulo 4. That is, the remainder when 173 is divided by 4. 173 = 1 mod 4 So the unit digit of 3127173 is the same as the unit digit of 7173 which is the unit digit of 71 which is 7.
9 and 4, respectively; the number will end in 49.
49 = 7 x 7
01.
Yes. One way is 3! + 5*7 + 9 = 6 + 35 + 9 = 50
There are only 4 prime digits: 2, 3, 5 and 7.There are only 4 prime digits: 2, 3, 5 and 7.There are only 4 prime digits: 2, 3, 5 and 7.There are only 4 prime digits: 2, 3, 5 and 7.
01
1.798465e42
The prime number is 47 and 4+7 = 11
6.004 x 107 = 6.004 x 10,000,000 = 60,040,000 Alternatively, in multiplying by a power of 10, move the decimal point the power number of digits right (positive) or left (negative), inserting zeros if you run out of digits: 6.004 x 107 the power of 10 is 7, so move decimal point 7 digits right after 3 moves run out of digits, so insert 4 zeros → 60,040,000. Multiplying by a negative power of 10 is the same as dividing by the positive power of 10, eg x 10-3 is the same as ÷ 103.
The answer, of over 100 digits can be found here: http://www.wolframalpha.com/input/?i=49%5E60
The unit of power in the cgs system is erg per second, where 1 erg is equal to 10^-7 joules.