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The least common multiple (LCM) of 57 and 29 is 1653.
57
571 = 57
Leaving aside the brute force method of trying all the number, The following is one way of reducing the number of possible solutions. You can elect, at any stage, to quit this process and try out each of the remaining possibilities. Max's number is odd. so it must be one of 43, 45, 47, 49, 51, 53, 57, 59, 61, 63. The difference between the digits is the same as the units digit which is odd. If the tens digit is 5, then the difference between 5 and the odd units digit would be even. That means the tens digit cannot be 5. Which leaves the following as possible solutions: 43, 45, 47, 49, 61, 63. Now, the tens digit is 4 or 6. The units digit must be between 1 and 9 (it is odd). so the difference between the tens and units digit must be 5 or fewer ie not 7 or 9. Then, since the difference is the same as the units digit, the units digit cannot be 7 or 9. So that leaves 43, 45, 61, 63. Now 43 an 45 both result in a difference of 1, not the units digit so neither can be a solution. That leaves 61 and 63. 61 has a digital difference of 5, not the units vaue which is 1. So 1 is not a possible answer and that leaves only 63. 6-3 = 3 so the difference is the same as the units digit. And that, my friend, is the answer - at long last!
The first (left most) digit is the number of tens and the other is the number of ones. So 57 = 5 tens plus 7 ones = 50 + 7 = 57
The least common multiple (LCM) of 57 and 29 is 1653.
57
Two digit no and the sum of the two digit give 12 39,48,57,66,75,84,93 are the possible two digit no whose sum is 12. Example 3+9=12;4+8=12...... Difference of the two digit no is 2 that is 57and75. because difference of 5 and 7 is 2. Next, unit digit to be greater than tens digit. So 57 is ans because 7 is in unit digit which is greater than tens digit.
29, 29, 29
27, 57, 77 and 87.
If you take the units digit and double it then subtract it from the rest of the number then the difference is divisible by seven. You may have to do it several times. 574 57-8=49 So it is a multiple of 7.
The answer is 1,653.
Mulitply before adding. 57*29 is 1653, +82 is 1735
Jeopardy - 1984 29-57 was released on: USA: 4 December 2012
571 = 57
11
Leaving aside the brute force method of trying all the number, The following is one way of reducing the number of possible solutions. You can elect, at any stage, to quit this process and try out each of the remaining possibilities. Max's number is odd. so it must be one of 43, 45, 47, 49, 51, 53, 57, 59, 61, 63. The difference between the digits is the same as the units digit which is odd. If the tens digit is 5, then the difference between 5 and the odd units digit would be even. That means the tens digit cannot be 5. Which leaves the following as possible solutions: 43, 45, 47, 49, 61, 63. Now, the tens digit is 4 or 6. The units digit must be between 1 and 9 (it is odd). so the difference between the tens and units digit must be 5 or fewer ie not 7 or 9. Then, since the difference is the same as the units digit, the units digit cannot be 7 or 9. So that leaves 43, 45, 61, 63. Now 43 an 45 both result in a difference of 1, not the units digit so neither can be a solution. That leaves 61 and 63. 61 has a digital difference of 5, not the units vaue which is 1. So 1 is not a possible answer and that leaves only 63. 6-3 = 3 so the difference is the same as the units digit. And that, my friend, is the answer - at long last!